Arithmetic  1
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Question 1 of 5
1. Question
If the Pth term of an Arithmetic Progression is 1/Q and the Qth term is 1/P, and the sum of the first PQ terms is 25PQ, then P & Q are connected by
Correct
tp = 1/q; tq = 1/p => Common difference ‘d’ = 1/pq and the first term ‘a’ = 1/pq
The sum of the first pq terms = 25pq = pq/2[2a + (pq1)d]
Simplifying, pq = 49Incorrect
tp = 1/q; tq = 1/p => Common difference ‘d’ = 1/pq and the first term ‘a’ = 1/pq
The sum of the first pq terms = 25pq = pq/2[2a + (pq1)d]
Simplifying, pq = 49 
Question 2 of 5
2. Question
A, B, C, D & E appeared for CAT 2016. The averages of their scores, taken three at a time are: 119, 121, 124, 125, 123, 126, 127, 128, 129 and 132. What is the highest individual score?
Correct
Incorrect

Question 3 of 5
3. Question
Had a trader bought an item at 10% less and sold it at 10% more, he would have doubled his profit percentage. What was the original profit percentage?
Correct
Incorrect

Question 4 of 5
4. Question
Mr. Cooper deposited $ p in HSBC in the beginning of 2010 @ 10% per annum (compounded annually ). He withdrew $ 500 at the end of every year. After having withdrawn $ 500 at the end of year 2012, he was left with no money in his account. What is the approximate value of P?
Correct
Let the principal be $ P.then
{(1.1P500)1.1500}1.1500=0
(1.1)^{3}P=1655
P=1243.43
Hence Option (d)
Incorrect
Let the principal be $ P.then
{(1.1P500)1.1500}1.1500=0
(1.1)^{3}P=1655
P=1243.43
Hence Option (d)

Question 5 of 5
5. Question
A container is filled up to half of its total volume with liquids L1 and L2 in the ratio 3 : 7. L1 and L2 evaporate at the rate of 25 litre/hr and 20 litre/hr respectively. After an hour the container is filled completely by adding another mixture which contains L1 and L2 in the ratio 2:3. The final ratio of L1 and L2 in the container becomes 1:2. What is the volume (in litres) of the container?
Correct
Let the volume (in litres) of the container be 200x. When container was filled up to half its volume:
Quantity (in litres) of L1 = 30x
Quantity (in litres) of L2 = 70xAfter an hour:
Quantity (in litres) of L1 remaining = 30x – 25
Quantity (in litres) of L2 remaining = 70x – 20
Quantity of L1 added = 40x + 18
Quantity of L2 added = 60x + 27
(70x – 7)/(130x + 7 ) = 1/2and 10x = 21
Volume of the container = 200x = 420 litres
Incorrect
Let the volume (in litres) of the container be 200x. When container was filled up to half its volume:
Quantity (in litres) of L1 = 30x
Quantity (in litres) of L2 = 70xAfter an hour:
Quantity (in litres) of L1 remaining = 30x – 25
Quantity (in litres) of L2 remaining = 70x – 20
Quantity of L1 added = 40x + 18
Quantity of L2 added = 60x + 27
(70x – 7)/(130x + 7 ) = 1/2and 10x = 21
Volume of the container = 200x = 420 litres